circuit {ResistorArray}R Documentation

Mensurates a circuit given potentials of some nodes

Description

Given a conductance matrix, a vector of potentials at each node, and a vector of current inputs at each node (NA being interpreted as “unknown”), this function determines the potentials and currents over the whole circuit.

Usage

circuit(L, v, currents=0, give.internal=FALSE)

Arguments

L Conductance matrix
v Vector of potentials; one element per node of the conductance matrix. Elements with NA are interpreted as “free” nodes, that is, nodes that are not kept at a fixed potential. The potential of these nodes is well defined by the other nodes in the problem. Note that such nodes will have known current inputs (which may be zero but must be specified by argument currents).
currents Vector of currents fed into each node. The only elements of this vector that are used are those that correspond to a node with free potential (use NA for nodes that are at a specified potential). The idea is that each node has either a specified voltage, or a specified current is fed into it; not both, and not neither.
Observe that feeding zero current into a node at free potential is perfectly acceptable (and the usual case).
give.internal Boolean, with TRUE meaning to return also a matrix showing the node to node currents, and default FALSE meaning to omit this.

Value

A list of 2 or 4 elements, depending on argument give.internal is FALSE or TRUE.

potentials A vector of potentials. Note that the potentials of the nodes whose potential was specified by input argument v retain their original potentials; symbolically all(potentials[!is.na(v)] == v[!is.na(v)]).
currents Vector of currents required to maintain the system with the potentials specified by input argument v
internal.currents Matrix showing current flow from node to node. Element [i,j] shows current flow from node i to node j.
power The power dissipated at each edge
total.power Total power dissipated over the resistor network

Note

The SI unit of potential is the “Volt”; the SI unit of current is the “Ampere”

Author(s)

Robin K. S. Hankin

See Also

resistance

Examples


#reproduce first example on ?cube:
v <- c(0,rep(NA,5),1,NA)
circuit(cube(),v)
circuit(cube(),v+1000)

#  problem: The nodes  of a skeleton cube are at potentials
#  1,2,3,... volts.  What current is needed to maintain this?  Ans:
circuit(cube(),1:8)

#sanity check: maintain one node at 101 volts:
circuit(cube(),c(rep(NA,7),101))

#now, nodes 1-4 have potential 1,2,3,4 volts.  Nodes 5-8 each have one
#Amp shoved in them.  What is the potential of nodes 5-8, and what
#current is needed to maintain nodes 1-4 at their potential?
# Answer:
v <- c(1:4,rep(NA,4))
currents <- c(rep(NA,4),rep(1,4))
circuit(cube(),v,currents)


[Package ResistorArray version 1.0-7 Index]