is.ok {magic}R Documentation

does a vector have the sum required to be a row or column of a magic square?

Description

Returns TRUE if and only if sum(vec)==magic.constant(n,d=d))

Usage

is.ok(vec, n=length(vec), d=2)

Arguments

vec Vector to be tested
n Order of square or hypercube. Default assumes order is equal to length of vec
d Dimension of square or hypercube. Default of 2 corresponds to a square

Author(s)

Robin K. S. Hankin

Examples

 is.ok(magic(5)[1,])


[Package magic version 1.4-4 Index]